Is csc^2(sin^2(x)-1)= 1/(cos^2(x)) ?

The answer to whether csc^2(sin^2(x)-1)= 1/(cos^2(x)) is False

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prove csc^2(sin^2(x)-1)= 1/(cos^2(x))

prove

csc^{2} (sin^{2} (x) - 1) = \frac{1}{cos ^{2} ( x )}

False

Solution steps

csc^{2} (sin^{2} (x) - 1) = \frac{1}{cos ^{2} ( x )}

Show that the two sides are not equal

\Rightarrow False

tan (θ^{2}) + 6 = sec (θ^{2}) + 5

sec^{2} (θ) = (sec^{2} (θ) - 1) \cdot csc^{2} (θ)

1 - cot^{2} (x) sin^{2} (x) = sin^{2} (x)

csc (ω) - sin (ω) = cot (ω) cos (ω)

\frac{cot ( 3 θ ) - tan ( 3 θ )}{sin ( 3 θ ) + cos ( 3 θ )} = csc (3 θ) - sec (3 θ)

Is csc^2(sin^2(x)-1)= 1/(cos^2(x)) ?
The answer to whether csc^2(sin^2(x)-1)= 1/(cos^2(x)) is False