Is cot(pi/2-θ)=(sin(θ))/(cos(θ)) ?

The answer to whether cot(pi/2-θ)=(sin(θ))/(cos(θ)) is True

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prove cot(pi/2-θ)=(sin(θ))/(cos(θ))

prove

cot (\frac{π}{2} - θ) = \frac{sin ( θ )}{cos ( θ )}

True

Solution steps

cot (\frac{π}{2} - θ) = \frac{sin ( θ )}{cos ( θ )}

Manipulating left side

cot (\frac{π}{2} - θ)

Rewrite using trig identities

= \frac{sin ( θ )}{cos ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

\frac{sec ^{2} ( x )}{tan ( x )} = tan (x) + cot (x)

tan^{2} (A) (csc^{2} (A) - 1) = 1

cos^{3} (θ) = - 1

1 + cos (x) = \frac{csc ( x ) + cot ( x )}{csc ( x )}

(tan (x)) (sin (x)) + (cos (x)) = sec (x)

Is cot(pi/2-θ)=(sin(θ))/(cos(θ)) ?
The answer to whether cot(pi/2-θ)=(sin(θ))/(cos(θ)) is True