Is (sec^2(x)cot(x))+cot(x)=tan(x) ?

The answer to whether (sec^2(x)cot(x))+cot(x)=tan(x) is False

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prove (sec^2(x)cot(x))+cot(x)=tan(x)

prove

(sec^{2} (x) cot (x)) + cot (x) = tan (x)

False

Solution steps

sec^{2} (x) cot (x) + cot (x) = tan (x)

Show that the two sides are not equal

For

sec^{2} (x) cot (x) + cot (x) = tan (x)

plug in

x = 1

sec^{2} (1) cot (1) + cot (1) = 2.84159 \dots

sec^{2} (1) cot (1) + cot (1)

Refine to a decimal form

= 2.84159 \dots

tan (1) = 1.55740 \dots

tan (1)

Refine to a decimal form

= 1.55740 \dots

The two sides are not equal

\Rightarrow False

cos (- \frac{1}{2}) = cos (\frac{2}{2})

(\frac{1}{2} sin^{2} (θ)) = (\frac{1}{2} cos (2 θ))

(sin (3 x) + cos (3 x))^{2} = 1 + sin (6 x)

sin (x - π) = sin (x) - sin (π)

cos (- \frac{2}{3} π) = cos (\frac{4 π}{3})

Is (sec^2(x)cot(x))+cot(x)=tan(x) ?
The answer to whether (sec^2(x)cot(x))+cot(x)=tan(x) is False