Is prove-2sin(2x+pi)=-2sin(2x-pi) ?

The answer to whether prove-2sin(2x+pi)=-2sin(2x-pi) is True

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prove-2sin(2x+pi)=-2sin(2x-pi)

prove

- 2 sin (2 x + π) = - 2 sin (2 x - π)

True

Solution steps

- 2 sin (2 x + π) = - 2 sin (2 x - π)

Manipulating left side

- 2 sin (2 x + π)

Rewrite using trig identities

= - 2 (- sin (2 x))

Apply rule

- (- a) = a

= 2 sin (2 x)

Manipulating right side

- 2 sin (2 x - π)

Rewrite using trig identities

= - 2 (- sin (2 x))

Apply rule

- (- a) = a

= 2 sin (2 x)

We showed that the two sides could take the same form

\Rightarrow True

cos (θ) (\frac{1}{1 - sin ( θ )}) = sec (θ) + tan (θ)

2 sin (a + b) sin (a - b) = cos (2 b) - cos (2 a)

\frac{1}{sin ( x )} = 2

(cos (θ) - sin (θ))^{2} = 1 + sin (2 θ)

(4 sin (θ) + 4 cos (θ)) = 16 + 16 sin (2 θ)

Is prove-2sin(2x+pi)=-2sin(2x-pi) ?
The answer to whether prove-2sin(2x+pi)=-2sin(2x-pi) is True