Is (cos(θ))/(sec(θ)-tan(θ))=1+sin(x) ?

The answer to whether (cos(θ))/(sec(θ)-tan(θ))=1+sin(x) is False

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prove (cos(θ))/(sec(θ)-tan(θ))=1+sin(x)

prove

\frac{cos ( θ )}{sec ( θ ) - tan ( θ )} = 1 + sin (x)

False

Solution steps

\frac{cos ( θ )}{sec ( θ ) - tan ( θ )} = 1 + sin (x)

Show that the two sides are not equal

\Rightarrow False

cos (x) = 1 - sin^{2} (2 x)

(sin (2 x))^{2} + (cos (2 x))^{2} = 1

1 - sin^{5} (x) = cos^{2} (x)

cot (\frac{π}{2} - θ) cot (θ) = 1

cos (\frac{x}{2}) (1 - cos (x)) = sin (\frac{x}{2}) sin (x)

Is (cos(θ))/(sec(θ)-tan(θ))=1+sin(x) ?
The answer to whether (cos(θ))/(sec(θ)-tan(θ))=1+sin(x) is False