Is cos^2(0)-sin^2(0)=1+sin(0) ?

The answer to whether cos^2(0)-sin^2(0)=1+sin(0) is True

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prove cos^2(0)-sin^2(0)=1+sin(0)

prove

cos^{2} (0) - sin^{2} (0) = 1 + sin (0)

True

Solution steps

cos^{2} (0) - sin^{2} (0) = 1 + sin (0)

Manipulating left side

cos^{2} (0) - sin^{2} (0)

Simplify

cos^{2} (0) - sin^{2} (0) : 1

= 1

Manipulating right side

1 + sin (0)

Simplify

1 + sin (0) : 1

= 1

We showed that the two sides could take the same form

\Rightarrow True

\frac{1 + sec ( x )}{csc ( x )} = cot (x) cos (x)

cos ((\frac{π}{2} - x) - 4) = sin (x + y)

\frac{1}{sec ( x ) ( tan ( x ) )} = csc (x) - sin (x)

\frac{2 sin ( x ) cos ( x ) sec ( x )}{2} = sin (x)

cos^{2} (x) + tan^{2} (x) cos^{2} (x) = sin (x)

Is cos^2(0)-sin^2(0)=1+sin(0) ?
The answer to whether cos^2(0)-sin^2(0)=1+sin(0) is True