Is 2sin(2x)+cot(2x)=csc(2x)-cos(2x) ?

The answer to whether 2sin(2x)+cot(2x)=csc(2x)-cos(2x) is False

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prove 2sin(2x)+cot(2x)=csc(2x)-cos(2x)

prove

2 sin (2 x) + cot (2 x) = csc (2 x) - cos (2 x)

False

Solution steps

2 sin (2 x) + cot (2 x) = csc (2 x) - cos (2 x)

Show that the two sides are not equal

\Rightarrow False

sin (\frac{3 π}{4}) = \frac{1}{2}

sin (c) = 2 sin (\frac{c}{2}) cos (\frac{c}{2})

\frac{5 sin ( 2 θ )}{2 sin ( θ )} = 5 cos (θ)

(1 - cos (x))^{2} = 1 + cos^{2} (x)

\frac{tan ( a ) + cot ( a )}{tan ( a )} = csc^{2} (a)

Is 2sin(2x)+cot(2x)=csc(2x)-cos(2x) ?
The answer to whether 2sin(2x)+cot(2x)=csc(2x)-cos(2x) is False