Is (1-sin(0))/(cos(0))=sec(0)-tan(0) ?

The answer to whether (1-sin(0))/(cos(0))=sec(0)-tan(0) is True

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prove (1-sin(0))/(cos(0))=sec(0)-tan(0)

prove

\frac{1 - sin ( 0 )}{cos ( 0 )} = sec (0) - tan (0)

True

Solution steps

\frac{1 - sin ( 0 )}{cos ( 0 )} = sec (0) - tan (0)

Manipulating left side

\frac{1 - sin ( 0 )}{cos ( 0 )}

Simplify

\frac{1 - sin ( 0 )}{cos ( 0 )} : 1

= 1

Manipulating right side

sec (0) - tan (0)

Simplify

sec (0) - tan (0) : 1

= 1

We showed that the two sides could take the same form

\Rightarrow True

cos (2 x - x) - 2 sin (x) sin (2 x) = cos (3 x)

2 (cos (3 θ) + 3 cos (θ)) = (2 cos (θ))^{3}

\frac{sin ( x ) tan ( x )}{cos ( x ) + 1} = tan (x)

tan^{2} (x) = sec^{2} (x) (1 - cos^{2} (x))

tan (x) = tan (x) csc^{2} (x) + cot (- x)

Is (1-sin(0))/(cos(0))=sec(0)-tan(0) ?
The answer to whether (1-sin(0))/(cos(0))=sec(0)-tan(0) is True