Is 7sec(θ)=(7sec(θ)-7)/(1-cos(θ)) ?

The answer to whether 7sec(θ)=(7sec(θ)-7)/(1-cos(θ)) is True

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prove 7sec(θ)=(7sec(θ)-7)/(1-cos(θ))

prove

7 sec (θ) = \frac{7 sec ( θ ) - 7}{1 - cos ( θ )}

True

Solution steps

7 sec (θ) = \frac{7 sec ( θ ) - 7}{1 - cos ( θ )}

Manipulating right side

\frac{7 sec ( θ ) - 7}{1 - cos ( θ )}

Express with sin, cos

= \frac{7}{cos ( θ )}

Rewrite using trig identities

7 sec (θ)

We showed that the two sides could take the same form

\Rightarrow True

2 tan (x) sin (x) - 3 cos (x) = 2

\frac{1 - ( cos ( - x ) )}{sec ( - x ) - 1} = cos (x)

\frac{2}{2} csc (x) - 1 = 0

cos (2 (\frac{7 π}{4}) - \frac{π}{2}) = - 1

sin (4 5^{\circ} + a) = sin (4 5^{\circ} - a)

Is 7sec(θ)=(7sec(θ)-7)/(1-cos(θ)) ?
The answer to whether 7sec(θ)=(7sec(θ)-7)/(1-cos(θ)) is True