What is the general solution for sin^2(2x)=1 ?

The general solution for sin^2(2x)=1 is x= pi/4+pin,x=(3pi)/4+pin

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sin^2(2x)=1

sin^{2} (2 x) = 1

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

sin^{2} (2 x) = 1

Solve by substitution

sin (2 x) = 1, sin (2 x) = - 1

sin (2 x) = 1 : x = \frac{π}{4} + πn

sin (2 x) = - 1 : x = \frac{3 π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

arctan (- \frac{240}{180})

sin (\frac{7 π}{12})

arccos (\frac{8}{20})

2 sin (x) + 3 = 0

csc (0)

What is the general solution for sin^2(2x)=1 ?
The general solution for sin^2(2x)=1 is x= pi/4+pin,x=(3pi)/4+pin