Is 1/(sin^2(θ))=1-tan^2(θ) ?

The answer to whether 1/(sin^2(θ))=1-tan^2(θ) is False

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove 1/(sin^2(θ))=1-tan^2(θ)

prove

\frac{1}{sin ^{2} ( θ )} = 1 - tan^{2} (θ)

False

Solution steps

\frac{1}{sin ^{2} ( θ )} = 1 - tan^{2} (θ)

Show that the two sides are not equal

\Rightarrow False

\frac{1}{( sec ( θ ) ) ^{2}} + \frac{1}{( csc ( θ ) ) ^{2}} = 1

sin^{2} (\frac{a}{2}) = \frac{1 - cos ( a )}{2}

tan (x) - tan (x) sin (x) = cos (x) sin (x)

cot (x) + tan (x) = sec (csc (x))

cos (\frac{1}{3} π) = cos (- \frac{1}{3} π)

Is 1/(sin^2(θ))=1-tan^2(θ) ?
The answer to whether 1/(sin^2(θ))=1-tan^2(θ) is False