Is (cos(k)-sec(k))^2=tan^2(-sin^2(k)) ?

The answer to whether (cos(k)-sec(k))^2=tan^2(-sin^2(k)) is False

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prove (cos(k)-sec(k))^2=tan^2(-sin^2(k))

prove

(cos (k) - sec (k))^{2} = tan^{2} (- sin^{2} (k))

False

Solution steps

(cos (k) - sec (k))^{2} = tan^{2} (- sin^{2} (k))

Show that the two sides are not equal

\Rightarrow False

sin (x) = tan^{2} (x) cos^{2} (x)

sin (2 x + x) = 3 sin (x) - 4 sin^{3} (x)

sin (3 x) = 2 \cdot sin (\frac{3 x}{2}) \cdot cos (\frac{3 x}{2})

(sec (a) - tan (a)) (csc (a) + 1) = cot (a)

- cos (x) sin^{2} (x) = - cos (x) (sin (x))^{2}

Is (cos(k)-sec(k))^2=tan^2(-sin^2(k)) ?
The answer to whether (cos(k)-sec(k))^2=tan^2(-sin^2(k)) is False