Is sec((5pi)/6)=(-2)/(sqrt(3)) ?

The answer to whether sec((5pi)/6)=(-2)/(sqrt(3)) is True

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prove sec((5pi)/6)=(-2)/(sqrt(3))

prove

sec (\frac{5 π}{6}) = \frac{- 2}{3}

True

Solution steps

sec (\frac{5 π}{6}) = \frac{- 2}{3}

Manipulating left side

sec (\frac{5 π}{6})

Simplify

= - \frac{2 3}{3}

Manipulating right side

\frac{- 2}{3}

Simplify

\frac{- 2}{3} : - \frac{2 3}{3}

= - \frac{2 3}{3}

We showed that the two sides could take the same form

\Rightarrow True

cos (ω) (sec (ω) - cos (ω)) = sin^{2} (ω)

\frac{sin ( θ )}{1 + cos ( θ )} + cot (θ) = csc (θ)

tan (x) csc (x) = tan (x) sin (x) + cos (x)

(cos (\frac{5 \cdot \frac{π}{3}}{4})) = (cos (5 \frac{π}{12}))

tan (2 1^{\circ}) = 2 tan (t)

Is sec((5pi)/6)=(-2)/(sqrt(3)) ?
The answer to whether sec((5pi)/6)=(-2)/(sqrt(3)) is True