Is (sin(60))/(1-cos(60))=cot(30) ?

The answer to whether (sin(60))/(1-cos(60))=cot(30) is True

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prove (sin(60))/(1-cos(60))=cot(30)

prove

\frac{sin ( 6 0 ^{\circ} )}{1 - cos ( 6 0 ^{\circ} )} = cot (3 0^{\circ})

True

Solution steps

\frac{sin ( 6 0 ^{\circ} )}{1 - cos ( 6 0 ^{\circ} )} = cot (3 0^{\circ})

Manipulating left side

\frac{sin ( 6 0 ^{\circ} )}{1 - cos ( 6 0 ^{\circ} )}

Simplify

\frac{sin ( 6 0 ^{\circ} )}{1 - cos ( 6 0 ^{\circ} )} : 3

= 3

Manipulating right side

cot (3 0^{\circ})

Simplify

= 3

We showed that the two sides could take the same form

\Rightarrow True

sin (2 x) + sin (x) = 0

\frac{cot ( θ )}{csc ( θ )} = cot (θ) csc (θ)

1 = cos (x) csc (x) tan (x)

csc^{2} (x) + sec^{2} (x) = 1

3 - 3 cos^{2} (x) + 4 - 4 sin^{2} (x) = 3 + cos^{2} (x)

Is (sin(60))/(1-cos(60))=cot(30) ?
The answer to whether (sin(60))/(1-cos(60))=cot(30) is True