Is csc(θ)-cot(θ)=(1-cos(θ))/(sin(θ)) ?

The answer to whether csc(θ)-cot(θ)=(1-cos(θ))/(sin(θ)) is True

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prove csc(θ)-cot(θ)=(1-cos(θ))/(sin(θ))

prove

csc (θ) - cot (θ) = \frac{1 - cos ( θ )}{sin ( θ )}

True

Solution steps

csc (θ) - cot (θ) = \frac{1 - cos ( θ )}{sin ( θ )}

Manipulating left side

csc (θ) - cot (θ)

Express with sin, cos

= \frac{1 - cos ( θ )}{sin ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

tan (x) = tan (x) + 2 sin^{2} (x)

\frac{1}{2 cot ( 1 - cos ^{2} ( x ) )} = csc (2 x)

2 cos (3 x) cos (3 x) = 1 - 2 sin (3 x) sin (2 x)

(1 + csc (x)) (1 - csc (x)) = - cot^{2} (x)

cot (u) = \frac{1}{tan ( u )}

Is csc(θ)-cot(θ)=(1-cos(θ))/(sin(θ)) ?
The answer to whether csc(θ)-cot(θ)=(1-cos(θ))/(sin(θ)) is True