Is sin^2(x)=sec(x)cos(x)-cos^2(x) ?

The answer to whether sin^2(x)=sec(x)cos(x)-cos^2(x) is True

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prove sin^2(x)=sec(x)cos(x)-cos^2(x)

prove

sin^{2} (x) = sec (x) cos (x) - cos^{2} (x)

True

Solution steps

sin^{2} (x) = sec (x) cos (x) - cos^{2} (x)

Manipulating right side

sec (x) cos (x) - cos^{2} (x)

Express with sin, cos

= 1 - cos^{2} (x)

Rewrite using trig identities

= sin^{2} (x)

We showed that the two sides could take the same form

\Rightarrow True

1 - 2 sin^{2} (2 θ) = 8 cos^{4} (θ) - 8 cos^{2} (θ) + 1

sech^{2} (x) + tanh^{2} (x) = 1

sec (x) cos (x) - 2 cos^{2} (x) = - (cos (2 x))

2 cos^{2} (A) - cos (2 A) - 1 = 0

\frac{( 2 sec ( x ) )}{tan ( x )} = 2 csc (x)

Is sin^2(x)=sec(x)cos(x)-cos^2(x) ?
The answer to whether sin^2(x)=sec(x)cos(x)-cos^2(x) is True