Is cot^2(θ)=(csc^2(θ))/(sec^2(θ)) ?

The answer to whether cot^2(θ)=(csc^2(θ))/(sec^2(θ)) is True

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prove cot^2(θ)=(csc^2(θ))/(sec^2(θ))

prove

cot^{2} (θ) = \frac{csc ^{2} ( θ )}{sec ^{2} ( θ )}

True

Solution steps

cot^{2} (θ) = \frac{csc ^{2} ( θ )}{sec ^{2} ( θ )}

Manipulating left side

cot^{2} (θ)

Express with sin, cos

= \frac{cos ^{2} ( θ )}{sin ^{2} ( θ )}

Rewrite using trig identities

\frac{csc ^{2} ( θ )}{sec ^{2} ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

\frac{1}{sec ( θ )} = arcsec (θ)

\frac{( cot ( x ) )}{( csc ( x ) )} = cos (x)

\frac{1 + cot ^{2} ( x )}{cot ^{2} ( x )} = sec^{2} (x)

sec^{2} (x) - tan^{2} (x) = sec (x) cos (x)

cos^{2} (4 x) = \frac{1}{2} + \frac{1}{2} cos (16 x)

Is cot^2(θ)=(csc^2(θ))/(sec^2(θ)) ?
The answer to whether cot^2(θ)=(csc^2(θ))/(sec^2(θ)) is True