Is (tan(θ)cot(θ))/(cos(θ))=sec(θ) ?

The answer to whether (tan(θ)cot(θ))/(cos(θ))=sec(θ) is True

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prove (tan(θ)cot(θ))/(cos(θ))=sec(θ)

prove

\frac{tan ( θ ) cot ( θ )}{cos ( θ )} = sec (θ)

True

Solution steps

\frac{tan ( θ ) cot ( θ )}{cos ( θ )} = sec (θ)

Manipulating left side

\frac{tan ( θ ) cot ( θ )}{cos ( θ )}

Express with sin, cos

\frac{cot ( θ ) tan ( θ )}{cos ( θ )}

Use the basic trigonometric identity:

cot (x) = \frac{cos ( x )}{sin ( x )}

= \frac{\frac{c o s ( θ )}{s i n ( θ )} tan ( θ )}{cos ( θ )}

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{\frac{c o s ( θ )}{s i n ( θ )} \cdot \frac{s i n ( θ )}{c o s ( θ )}}{cos ( θ )}

Simplify

\frac{\frac{c o s ( θ )}{s i n ( θ )} \cdot \frac{s i n ( θ )}{c o s ( θ )}}{cos ( θ )} : \frac{1}{cos ( θ )}

\frac{\frac{c o s ( θ )}{s i n ( θ )} \cdot \frac{s i n ( θ )}{c o s ( θ )}}{cos ( θ )}

Multiply

\frac{cos ( θ )}{sin ( θ )} \cdot \frac{sin ( θ )}{cos ( θ )} : 1

\frac{cos ( θ )}{sin ( θ )} \cdot \frac{sin ( θ )}{cos ( θ )}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{cos ( θ ) sin ( θ )}{sin ( θ ) cos ( θ )}

Cancel the common factor:

cos (θ)

= \frac{sin ( θ )}{sin ( θ )}

Cancel the common factor:

sin (θ)

= 1

= \frac{1}{cos ( θ )}

= \frac{1}{cos ( θ )}

= \frac{1}{cos ( θ )}

Rewrite using trig identities

Use the basic trigonometric identity:

cos (x) = \frac{1}{sec ( x )}

\frac{1}{\frac{1}{s e c ( θ )}}

Simplify

\frac{1}{\frac{1}{s e c ( θ )}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{sec ( θ )}{1}

Apply rule

\frac{a}{1} = a

= sec (θ)

sec (θ)

sec (θ)

We showed that the two sides could take the same form

\Rightarrow True

2 (cos (θ - 1))^{2} = cos^{4} (θ) - sin^{4} (θ)

\frac{sec ^{2} ( \frac{x}{2} )}{2} = \frac{1}{1 + cos ( x )}

cos (x) = \frac{15}{17}

tan (b) + cot (b) = \frac{1}{sin ( b ) cos ( b )}

csc (A) - sin (A) = (cos (A)) (cot (A))

Is (tan(θ)cot(θ))/(cos(θ))=sec(θ) ?
The answer to whether (tan(θ)cot(θ))/(cos(θ))=sec(θ) is True