Is 5cos^2(x)-2cos(x)-3-sin^2(x)=0 ?

The answer to whether 5cos^2(x)-2cos(x)-3-sin^2(x)=0 is False

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prove 5cos^2(x)-2cos(x)-3-sin^2(x)=0

prove

5 cos^{2} (x) - 2 cos (x) - 3 - sin^{2} (x) = 0

False

Solution steps

5 cos^{2} (x) - 2 cos (x) - 3 - sin^{2} (x) = 0

Show that the two sides are not equal

For

5 cos^{2} (x) - 2 cos (x) - 3 - sin^{2} (x) = 0

plug in

x = 1

5 cos^{2} (1) - 2 cos (1) - 3 - sin^{2} (1) = - 3.32904 \dots

5 cos^{2} (1) - 2 cos (1) - 3 - sin^{2} (1)

Refine to a decimal form

= - 3.32904 \dots

The two sides are not equal

\Rightarrow False

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cos^{4} (a) + 1 - sin^{4} (a) = 2 cos^{2} (a)

3 - 4 cos^{2} (x) = (2 sin (x) + 1) (2 sin (x) - 1)

csc^{2} (θ) = (\frac{1}{sin ( θ )})^{2}

\frac{1 + tan ( x )}{1 + \frac{1}{t a n ( x )}} = tan (x)

Is 5cos^2(x)-2cos(x)-3-sin^2(x)=0 ?
The answer to whether 5cos^2(x)-2cos(x)-3-sin^2(x)=0 is False