Is (cos(2θ))/(-sin^2(θ))=cos^2(θ) ?

The answer to whether (cos(2θ))/(-sin^2(θ))=cos^2(θ) is False

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prove (cos(2θ))/(-sin^2(θ))=cos^2(θ)

prove

\frac{cos ( 2 θ )}{- sin ^{2} ( θ )} = cos^{2} (θ)

False

Solution steps

\frac{cos ( 2 θ )}{- sin ^{2} ( θ )} = cos^{2} (θ)

Show that the two sides are not equal

\Rightarrow False

\frac{1}{cos ^{3} ( x )} = sec^{3} (x)

sin (x) + cot (x) (cos (x)) = csc (x)

\frac{1}{csc ( x ) - 1} = \frac{sin ( x )}{1}

\frac{1 - ( cos ( x ) )}{sec ( x ) - 1} = cos (x)

sec (θ) cos (θ) csc (θ) = cot (θ)

Is (cos(2θ))/(-sin^2(θ))=cos^2(θ) ?
The answer to whether (cos(2θ))/(-sin^2(θ))=cos^2(θ) is False