Is cot(60)=(cos(60))/(sin(60)) ?

The answer to whether cot(60)=(cos(60))/(sin(60)) is True

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prove cot(60)=(cos(60))/(sin(60))

prove

cot (6 0^{\circ}) = \frac{cos ( 6 0 ^{\circ} )}{sin ( 6 0 ^{\circ} )}

True

Solution steps

cot (6 0^{\circ}) = \frac{cos ( 6 0 ^{\circ} )}{sin ( 6 0 ^{\circ} )}

Use the basic trigonometric identity:

cot (x) = \frac{cos ( x )}{sin ( x )}

\Rightarrow True

\frac{sec ( x )}{cos ( x )} = sec^{2} (x)

tan (- x) tan (\frac{π}{2} - x) = - 1

tan (z) \cdot cos (z) \cdot csc (z) = 1

tan (π - θ) = - tan (x)

cot (θ) (sin (θ) + tan (θ)) = cos (θ) + 1

Is cot(60)=(cos(60))/(sin(60)) ?
The answer to whether cot(60)=(cos(60))/(sin(60)) is True