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Popular >

-0.25<= 0.5sin(2x)

Solution

- 0.25 \leq 0.5 sin (2 x)

Solution

- \frac{π}{12} + πn \leq x \leq \frac{7 π}{12} + πn

Interval Notation

[- \frac{π}{12} + πn, \frac{7 π}{12} + πn]

Decimal Notation

- 0.26179 \dots + πn \leq x \leq 1.83259 \dots + πn

Solution steps

- 0.25 \leq 0.5 sin (2 x)

Switch sides

0.5 sin (2 x) \geq - 0.25

Divide both sides by

0.5

0.5 sin (2 x) \geq - 0.25

Divide both sides by

0.5

\frac{0.5 sin ( 2 x )}{0.5} \geq \frac{- 0.25}{0.5}

Simplify

\frac{0.5 sin ( 2 x )}{0.5} \geq \frac{- 0.25}{0.5}

Simplify

\frac{0.5 sin ( 2 x )}{0.5} : sin (2 x)

\frac{0.5 sin ( 2 x )}{0.5}

Cancel the common factor:

0.5

= sin (2 x)

Simplify

\frac{- 0.25}{0.5} : - 0.5

\frac{- 0.25}{0.5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{0.25}{0.5}

Divide the numbers:

\frac{0.25}{0.5} = 0.5

= - 0.5

sin (2 x) \geq - 0.5

sin (2 x) \geq - 0.5

sin (2 x) \geq - 0.5

For

sin (x) \geq a

, if

- 1 < a < 1

then

arcsin (a) + 2 πn \leq x \leq π - arcsin (a) + 2 πn

arcsin (- 0.5) + 2 πn \leq 2 x \leq π - arcsin (- 0.5) + 2 πn

a \leq u \leq b

then

a \leq u and u \leq b

arcsin (- 0.5) + 2 πn \leq 2 x and 2 x \leq π - arcsin (- 0.5) + 2 πn

arcsin (- 0.5) + 2 πn \leq 2 x : x \geq - \frac{π}{12} + πn

arcsin (- 0.5) + 2 πn \leq 2 x

Switch sides

2 x \geq arcsin (- 0.5) + 2 πn

Simplify

arcsin (- 0.5) + 2 πn : - \frac{π}{6} + 2 πn

arcsin (- 0.5) + 2 πn

arcsin (- 0.5) = - \frac{π}{6}

arcsin (- 0.5)

= arcsin (- \frac{1}{2})

Use the following property:

arcsin (- x) = - arcsin (x)

arcsin (- \frac{1}{2}) = - arcsin (\frac{1}{2})

= - arcsin (\frac{1}{2})

Use the following trivial identity:

arcsin (\frac{1}{2}) = \frac{π}{6}

arcsin (\frac{1}{2})

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{6}

= - \frac{π}{6}

= - \frac{π}{6} + 2 πn

2 x \geq - \frac{π}{6} + 2 πn

Divide both sides by

2

2 x \geq - \frac{π}{6} + 2 πn

Divide both sides by

2

\frac{2 x}{2} \geq - \frac{\frac{π}{6}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} \geq - \frac{\frac{π}{6}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

- \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} : - \frac{π}{12} + πn

- \frac{\frac{π}{6}}{2} + \frac{2 πn}{2}

\frac{\frac{π}{6}}{2} = \frac{π}{12}

\frac{\frac{π}{6}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{6 \cdot 2}

Multiply the numbers:

6 \cdot 2 = 12

= \frac{π}{12}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

= - \frac{π}{12} + πn

x \geq - \frac{π}{12} + πn

x \geq - \frac{π}{12} + πn

x \geq - \frac{π}{12} + πn

2 x \leq π - arcsin (- 0.5) + 2 πn : x \leq \frac{7 π}{12} + πn

2 x \leq π - arcsin (- 0.5) + 2 πn

Simplify

π - arcsin (- 0.5) + 2 πn : π + \frac{π}{6} + 2 πn

π - arcsin (- 0.5) + 2 πn

arcsin (- 0.5) = - \frac{π}{6}

arcsin (- 0.5)

= arcsin (- \frac{1}{2})

Use the following property:

arcsin (- x) = - arcsin (x)

arcsin (- \frac{1}{2}) = - arcsin (\frac{1}{2})

= - arcsin (\frac{1}{2})

Use the following trivial identity:

arcsin (\frac{1}{2}) = \frac{π}{6}

arcsin (\frac{1}{2})

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{6}

= - \frac{π}{6}

= π - (- \frac{π}{6}) + 2 πn

Apply rule

- (- a) = a

= π + \frac{π}{6} + 2 πn

2 x \leq π + \frac{π}{6} + 2 πn

Divide both sides by

2

2 x \leq π + \frac{π}{6} + 2 πn

Divide both sides by

2

\frac{2 x}{2} \leq \frac{π}{2} + \frac{\frac{π}{6}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} \leq \frac{π}{2} + \frac{\frac{π}{6}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{π}{2} + \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} : \frac{π}{2} + \frac{π}{12} + πn

\frac{π}{2} + \frac{\frac{π}{6}}{2} + \frac{2 πn}{2}

\frac{\frac{π}{6}}{2} = \frac{π}{12}

\frac{\frac{π}{6}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{6 \cdot 2}

Multiply the numbers:

6 \cdot 2 = 12

= \frac{π}{12}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

= \frac{π}{2} + \frac{π}{12} + πn

x \leq \frac{π}{2} + \frac{π}{12} + πn

x \leq \frac{π}{2} + \frac{π}{12} + πn

Simplify

\frac{π}{2} + \frac{π}{12} : \frac{7 π}{12}

\frac{π}{2} + \frac{π}{12}

Least Common Multiplier of

2, 12 : 12

2, 12

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

12 : 2 \cdot 2 \cdot 3

12

12

divides by

212 = 6 \cdot 2

= 2 \cdot 6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 3

Multiply each factor the greatest number of times it occurs in either

2

12

= 2 \cdot 2 \cdot 3

Multiply the numbers:

2 \cdot 2 \cdot 3 = 12

= 12

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

12

For

\frac{π}{2} :

multiply the denominator and numerator by

6

\frac{π}{2} = \frac{π 6}{2 \cdot 6} = \frac{π 6}{12}

= \frac{π 6}{12} + \frac{π}{12}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π 6 + π}{12}

Add similar elements:

6 π + π = 7 π

= \frac{7 π}{12}

x \leq \frac{7 π}{12} + πn

x \leq \frac{7 π}{12} + πn

Combine the intervals

x \geq - \frac{π}{12} + πn and x \leq \frac{7 π}{12} + πn

Merge Overlapping Intervals

- \frac{π}{12} + πn \leq x \leq \frac{7 π}{12} + πn

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