What is the value of cot(arcsec(41/9)) ?

The value of cot(arcsec(41/9)) is 9/40

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cot(arcsec(41/9))

cot (arcsec (\frac{41}{9}))

\frac{9}{40}

Decimal Notation

0.225

Solution steps

cot (arcsec (\frac{41}{9}))

Rewrite using trig identities:

cot (arcsec (\frac{41}{9})) = \frac{1}{( \frac{41}{9} ) 1 - \frac{1}{( \frac{41}{9} ) ^{2}}}

Use the following identity:

cot (arcsec (x)) = \frac{1}{x 1 - \frac{1}{x ^{2}}}

= \frac{1}{( \frac{41}{9} ) 1 - \frac{1}{( \frac{41}{9} ) ^{2}}}

= \frac{1}{\frac{41}{9} 1 - \frac{1}{( \frac{41}{9} ) ^{2}}}

Simplify

= \frac{9}{40}

tan (arcsin (\frac{1}{2}) + arccos (- \frac{3}{2}))

6 cos (10 5^{\circ}) + 6 cos (1 5^{\circ})

6 cos (13 5^{\circ}) - 6 cos (4 5^{\circ})

\frac{sin ( 15 0 ^{\circ} )}{1 + cos ( 15 0 ^{\circ} )}

- 3 sin (2 5^{\circ})