What is the general solution for sin(θ)sin(2θ)=0 ?

The general solution for sin(θ)sin(2θ)=0 is θ=pin,θ= pi/2+pin

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sin(θ)sin(2θ)=0

sin (θ) sin (2 θ) = 0

θ = πn, θ = \frac{π}{2} + πn

Solution steps

sin (θ) sin (2 θ) = 0

Solving each part separately

sin (θ) = 0 or sin (2 θ) = 0

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

sin (2 θ) = 0 : θ = πn, θ = \frac{π}{2} + πn

Combine all the solutions

θ = 2 πn, θ = π + 2 πn, θ = πn, θ = \frac{π}{2} + πn

Merge Overlapping Intervals

θ = πn, θ = \frac{π}{2} + πn

sin (\frac{11 π}{6})

tan (\frac{11 π}{6})

2 sin (θ) - 3 = 0

sec^{2} (\frac{π}{3})

cos (\frac{13 π}{4})

What is the general solution for sin(θ)sin(2θ)=0 ?
The general solution for sin(θ)sin(2θ)=0 is θ=pin,θ= pi/2+pin