What is the value of cot(arccos(-7/25)) ?

The value of cot(arccos(-7/25)) is -7/24

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cot(arccos(-7/25))

cot (arccos (- \frac{7}{25}))

- \frac{7}{24}

Decimal Notation

- 0.29166 \dots

Solution steps

cot (arccos (- \frac{7}{25}))

Rewrite using trig identities:

cot (arccos (- \frac{7}{25})) = \frac{( - \frac{7}{25} )}{1 - ( - \frac{7}{25} ) ^{2}}

Use the following identity:

cot (arccos (x)) = \frac{x}{1 - x ^{2}}

= \frac{( - \frac{7}{25} )}{1 - ( - \frac{7}{25} ) ^{2}}

= \frac{- \frac{7}{25}}{1 - ( - \frac{7}{25} ) ^{2}}

Simplify

= - \frac{7}{24}

sin (4 5^{\circ}) (tan (4 5^{\circ}) - cos (6 0^{\circ}))

602 cos (4 5^{\circ})

tan (\frac{7 π}{9})

arctan (\frac{12.1024}{12})

arccos (cos (\frac{2 π}{3})) + arcsin (sin (\frac{2 π}{3}))

What is the value of cot(arccos(-7/25)) ?
The value of cot(arccos(-7/25)) is -7/24