What is the value of 2cos(pi/6)+sin((5pi)/6)-tan(pi/3) ?

The value of 2cos(pi/6)+sin((5pi)/6)-tan(pi/3) is 1/2

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2cos(pi/6)+sin((5pi)/6)-tan(pi/3)

2 cos (\frac{π}{6}) + sin (\frac{5 π}{6}) - tan (\frac{π}{3})

\frac{1}{2}

Solution steps

2 cos (\frac{π}{6}) + sin (\frac{5 π}{6}) - tan (\frac{π}{3})

Use the following trivial identity:

cos (\frac{π}{6}) = \frac{3}{2}

Use the following trivial identity:

sin (\frac{5 π}{6}) = \frac{1}{2}

Use the following trivial identity:

tan (\frac{π}{3}) = 3

= 2 \cdot \frac{3}{2} + \frac{1}{2} - 3

Simplify

2 \cdot \frac{3}{2} + \frac{1}{2} - 3 : \frac{1}{2}

= \frac{1}{2}

e^{s i n (0)} cos^{2} (0) - e^{s i n (0)} sin (0)

- 2 (- 2 sech^{2} (0) tanh^{2} (0) + sech^{4} (0))

arctan (0.67)

\frac{sin ^{3} ( \frac{π}{2} )}{3}

sin (20. 5^{\circ})

What is the value of 2cos(pi/6)+sin((5pi)/6)-tan(pi/3) ?
The value of 2cos(pi/6)+sin((5pi)/6)-tan(pi/3) is 1/2