What is the value of arccos(sin((5pi)/2)) ?

The value of arccos(sin((5pi)/2)) is 0

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arccos(sin((5pi)/2))

arccos (sin (\frac{5 π}{2}))

0

Solution steps

arccos (sin (\frac{5 π}{2}))

Rewrite using trig identities:

sin (\frac{5 π}{2}) = cos (- 2 π)

= arccos (cos (- 2 π))

Use the inverse trig property:

0

= 0

4 sin (18 0^{\circ})

sin (\frac{7 π}{8}) - sin (\frac{7 π}{6}) - cot (\frac{π}{3})

2 sin (6 0^{\circ}) sec (3 0^{\circ}) cos (4 5^{\circ}) tan (4 5^{\circ})

3 + 2 sin (\frac{π}{4})

cos (3 0^{\circ}) + tan (4 5^{\circ})

What is the value of arccos(sin((5pi)/2)) ?
The value of arccos(sin((5pi)/2)) is 0