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Popular >

coth(2)

Solution

coth (2)

Solution

\frac{e ^{4} + 1}{e ^{4} - 1}

+1

Solution steps

coth (2)

Use the Hyperbolic identity:

coth (x) = \frac{e ^{x} + e ^{- x}}{e ^{x} - e ^{- x}}

= \frac{e ^{2} + e ^{- 2}}{e ^{2} - e ^{- 2}}

\frac{e ^{2} + e ^{- 2}}{e ^{2} - e ^{- 2}} = \frac{e ^{4} + 1}{e ^{4} - 1}

= \frac{e ^{4} + 1}{e ^{4} - 1}

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Frequently Asked Questions (FAQ)

What is the value of coth(2) ?
The value of coth(2) is (e^4+1)/(e^4-1)