What is the value of cos(120)+tan(315)-sin(210) ?

The value of cos(120)+tan(315)-sin(210) is -1

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cos(120)+tan(315)-sin(210)

cos (12 0^{\circ}) + tan (31 5^{\circ}) - sin (21 0^{\circ})

- 1

Solution steps

cos (12 0^{\circ}) + tan (31 5^{\circ}) - sin (21 0^{\circ})

Use the following trivial identity:

cos (12 0^{\circ}) = - \frac{1}{2}

Rewrite using trig identities:

tan (31 5^{\circ}) = - 1

Rewrite using trig identities:

sin (21 0^{\circ}) = - \frac{1}{2}

= - \frac{1}{2} - 1 - (- \frac{1}{2})

Simplify

= - 1

60 sin (2 5^{\circ})

- cos (\frac{π}{3}) + cos (0)

arccos (0.998482)

csc (\frac{3}{2})

4 + 3 cos (0)

What is the value of cos(120)+tan(315)-sin(210) ?
The value of cos(120)+tan(315)-sin(210) is -1