What is the value of (sin(60))(cos(30))+tan(45) ?

The value of (sin(60))(cos(30))+tan(45) is 7/4

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(sin(60))(cos(30))+tan(45)

(sin (6 0^{\circ})) (cos (3 0^{\circ})) + tan (4 5^{\circ})

\frac{7}{4}

Solution steps

(sin (6 0^{\circ})) (cos (3 0^{\circ})) + tan (4 5^{\circ})

= sin (6 0^{\circ}) cos (3 0^{\circ}) + tan (4 5^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

Use the following trivial identity:

cos (3 0^{\circ}) = \frac{3}{2}

Use the following trivial identity:

tan (4 5^{\circ}) = 1

= \frac{3}{2} \cdot \frac{3}{2} + 1

Simplify

\frac{3}{2} \cdot \frac{3}{2} + 1 : \frac{7}{4}

= \frac{7}{4}

sec (\frac{7 π}{6}) - cot (\frac{5 π}{6})

cot (\frac{6 π}{5})

\frac{13}{tan ( 9 0 ^{\circ} )}

\frac{150}{sin ( 1 5 ^{\circ} )}

tan (21 5^{\circ})

What is the value of (sin(60))(cos(30))+tan(45) ?
The value of (sin(60))(cos(30))+tan(45) is 7/4