What is the value of -cos((3pi)/4)+cos(pi/2) ?

The value of -cos((3pi)/4)+cos(pi/2) is (sqrt(2))/2

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-cos((3pi)/4)+cos(pi/2)

- cos (\frac{3 π}{4}) + cos (\frac{π}{2})

\frac{2}{2}

Decimal Notation

0.70710 \dots

Solution steps

- cos (\frac{3 π}{4}) + cos (\frac{π}{2})

Use the following trivial identity:

cos (\frac{3 π}{4}) = - \frac{2}{2}

cos (\frac{3 π}{4})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - \frac{2}{2}

Use the following trivial identity:

cos (\frac{π}{2}) = 0

cos (\frac{π}{2})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 0

= - (- \frac{2}{2}) + 0

Simplify

= \frac{2}{2}

cos^{6} (0)

\frac{5}{π} - arccos (\frac{50}{110})

4 cos^{2} (6 0^{\circ}) + 3 tan (3 0^{\circ})

cos (π - \frac{π}{3})

\frac{12.2}{sin ( 4 0 ^{\circ} )}

What is the value of -cos((3pi)/4)+cos(pi/2) ?
The value of -cos((3pi)/4)+cos(pi/2) is (sqrt(2))/2