What is the value of sin^2(45)+tan^2(60) ?

The value of sin^2(45)+tan^2(60) is 7/2

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sin^2(45)+tan^2(60)

sin^{2} (4 5^{\circ}) + tan^{2} (6 0^{\circ})

\frac{7}{2}

Solution steps

sin^{2} (4 5^{\circ}) + tan^{2} (6 0^{\circ})

Use the following trivial identity:

sin (4 5^{\circ}) = \frac{2}{2}

Use the following trivial identity:

tan (6 0^{\circ}) = 3

= (\frac{2}{2})^{2} + (3)^{2}

Simplify

(\frac{2}{2})^{2} + (3)^{2} : \frac{7}{2}

= \frac{7}{2}

tan (\frac{536}{- 3928})

sin (9.8)

- 2 sec (4 5^{\circ})

sin^{2} (0.2)

cosh^{2} (1)

What is the value of sin^2(45)+tan^2(60) ?
The value of sin^2(45)+tan^2(60) is 7/2