What is the value of -100sin(60) ?

The value of -100sin(60) is -50sqrt(3)

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-100sin(60)

- 100 sin (6 0^{\circ})

- 503

Decimal Notation

- 86.60254 \dots

Solution steps

- 100 sin (6 0^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= - 100 \cdot \frac{3}{2}

Simplify

- 100 \cdot \frac{3}{2} : - 503

- 100 \cdot \frac{3}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{3 \cdot 100}{2}

Divide the numbers:

\frac{100}{2} = 50

= - 503

= - 503

50 sin (2 5^{\circ})

arctan (4) - arctan (\frac{3}{5})

cos (48.5 9^{\circ})

sec (6 0^{\circ}) + csc (3 0^{\circ})

sin^{2} (3 2^{\circ}) + cos^{2} (3 2^{\circ})