What is the general solution for 2sin(x)-1=0 ?

The general solution for 2sin(x)-1=0 is x= pi/6+2pin,x=(5pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin(x)-1=0

2 sin (x) - 1 = 0

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

Solution steps

2 sin (x) - 1 = 0

Move

1

to the right side

2 sin (x) = 1

Divide both sides by

2

sin (x) = \frac{1}{2}

General solutions for

sin (x) = \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

cos (x) + sin (x) = 0

cos (x) + sin (x) tan (x) = 2

tan (θ) = \frac{3}{3}

cos (\frac{x}{2}) = \frac{2}{2}

sin (10 5^{\circ})

What is the general solution for 2sin(x)-1=0 ?
The general solution for 2sin(x)-1=0 is x= pi/6+2pin,x=(5pi)/6+2pin