What is the value of (cos(arcsin(1/2)))/(tan(arccos(-1/2))) ?

The value of (cos(arcsin(1/2)))/(tan(arccos(-1/2))) is -1/2

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(cos(arcsin(1/2)))/(tan(arccos(-1/2)))

\frac{cos ( arcsin ( \frac{1}{2} ) )}{tan ( arccos ( - \frac{1}{2} ) )}

- \frac{1}{2}

Solution steps

\frac{cos ( arcsin ( \frac{1}{2} ) )}{tan ( arccos ( - \frac{1}{2} ) )}

Rewrite using trig identities:

cos (arcsin (\frac{1}{2})) = \frac{3}{2}

Rewrite using trig identities:

tan (arccos (- \frac{1}{2})) = - 3

= \frac{\frac{3}{2}}{- 3}

Simplify

\frac{\frac{3}{2}}{- 3} : - \frac{1}{2}

= - \frac{1}{2}

\frac{π}{3} - sin (\frac{π}{3})

cos (187. 5^{\circ})

1 + cos (12 0^{\circ})

2 - 2 cosh (1)

\frac{cot ^{2} ( 3 5 ^{\circ} )}{cot ^{2} ( 2 5 ^{\circ} )}

What is the value of (cos(arcsin(1/2)))/(tan(arccos(-1/2))) ?
The value of (cos(arcsin(1/2)))/(tan(arccos(-1/2))) is -1/2