What is the value of (cos(60)-sin(60)+tan(60))/(sin(60)) ?

The value of (cos(60)-sin(60)+tan(60))/(sin(60)) is (sqrt(3)+3)/3

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(cos(60)-sin(60)+tan(60))/(sin(60))

\frac{cos ( 6 0 ^{\circ} ) - sin ( 6 0 ^{\circ} ) + tan ( 6 0 ^{\circ} )}{sin ( 6 0 ^{\circ} )}

\frac{3 + 3}{3}

Solution steps

\frac{cos ( 6 0 ^{\circ} ) - sin ( 6 0 ^{\circ} ) + tan ( 6 0 ^{\circ} )}{sin ( 6 0 ^{\circ} )}

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

Use the following trivial identity:

tan (6 0^{\circ}) = 3

= \frac{\frac{1}{2} - \frac{3}{2} + 3}{\frac{3}{2}}

Simplify

\frac{\frac{1}{2} - \frac{3}{2} + 3}{\frac{3}{2}} : \frac{3 + 3}{3}

= \frac{3 + 3}{3}

arccos (\frac{9}{41})

arccos (1.21)

ln (3) - \frac{1}{2} ln (5) + arctan (3) - \frac{π}{4}

cos (56. 3^{\circ})

arctan (\frac{13}{15})

What is the value of (cos(60)-sin(60)+tan(60))/(sin(60)) ?
The value of (cos(60)-sin(60)+tan(60))/(sin(60)) is (sqrt(3)+3)/3