What is the value of -4sin(12(pi/8))-3cos(12(pi/8)) ?

The value of -4sin(12(pi/8))-3cos(12(pi/8)) is 4

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-4sin(12(pi/8))-3cos(12(pi/8))

- 4 sin (12 (\frac{π}{8})) - 3 cos (12 (\frac{π}{8}))

4

Solution steps

- 4 sin (12 (\frac{π}{8})) - 3 cos (12 (\frac{π}{8}))

= - 4 sin (12 \cdot \frac{π}{8}) - 3 cos (12 \cdot \frac{π}{8})

Simplify:

12 \cdot \frac{π}{8} = \frac{3 π}{2}

= - 4 sin (\frac{3 π}{2}) - 3 cos (\frac{3 π}{2})

Rewrite using trig identities:

sin (\frac{3 π}{2}) = - 1

Rewrite using trig identities:

cos (\frac{3 π}{2}) = 0

= - 4 (- 1) - 3 \cdot 0

Simplify

= 4

- 3 sin (\frac{3 π}{4})

100 tan (3 0^{\circ})

sin (189 0^{\circ})

1 \cdot cos (0)

- arctan (3)

What is the value of -4sin(12(pi/8))-3cos(12(pi/8)) ?
The value of -4sin(12(pi/8))-3cos(12(pi/8)) is 4