What is the value of sin^2(60)+cos^2(45) ?

The value of sin^2(60)+cos^2(45) is 5/4

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sin^2(60)+cos^2(45)

sin^{2} (6 0^{\circ}) + cos^{2} (4 5^{\circ})

\frac{5}{4}

Solution steps

sin^{2} (6 0^{\circ}) + cos^{2} (4 5^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

Use the following trivial identity:

cos (4 5^{\circ}) = \frac{2}{2}

= (\frac{3}{2})^{2} + (\frac{2}{2})^{2}

Simplify

(\frac{3}{2})^{2} + (\frac{2}{2})^{2} : \frac{5}{4}

= \frac{5}{4}

cos (arcsin (- 0.732))

sin^{2} (0.8)

arctan (1.07)

sin (12 4^{\circ})

3 tan (3 0^{\circ})

What is the value of sin^2(60)+cos^2(45) ?
The value of sin^2(60)+cos^2(45) is 5/4