What is the value of tan^2(pi/4)+sin^2(pi/6)+cos^2(pi/6) ?

The value of tan^2(pi/4)+sin^2(pi/6)+cos^2(pi/6) is 2

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tan^2(pi/4)+sin^2(pi/6)+cos^2(pi/6)

tan^{2} (\frac{π}{4}) + sin^{2} (\frac{π}{6}) + cos^{2} (\frac{π}{6})

2

Solution steps

tan^{2} (\frac{π}{4}) + sin^{2} (\frac{π}{6}) + cos^{2} (\frac{π}{6})

Use the following trivial identity:

tan (\frac{π}{4}) = 1

Use the following trivial identity:

sin (\frac{π}{6}) = \frac{1}{2}

Use the following trivial identity:

cos (\frac{π}{6}) = \frac{3}{2}

= 1^{2} + (\frac{1}{2})^{2} + (\frac{3}{2})^{2}

Simplify

1^{2} + (\frac{1}{2})^{2} + (\frac{3}{2})^{2} : 2

= 2

cos (arccos (\frac{15}{17}) - arccos (\frac{7}{25}))

\frac{5 π}{6} + 2 cos (\frac{5 π}{6})

arctan (\frac{0.1}{cos ( 3 )})

\frac{tan ( 5 0 ^{\circ} )}{cot ( 4 0 ^{\circ} )} + \frac{5 csc ( 2 0 ^{\circ} )}{sec ( 7 0 ^{\circ} )}

sec^{2} (arctan (2)) + csc^{2} (arccot (3))

What is the value of tan^2(pi/4)+sin^2(pi/6)+cos^2(pi/6) ?
The value of tan^2(pi/4)+sin^2(pi/6)+cos^2(pi/6) is 2