What is the value of e^{cos(0)}sin^2(0)-e^{cos(0)}cos(0) ?

The value of e^{cos(0)}sin^2(0)-e^{cos(0)}cos(0) is -e

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e^{cos(0)}sin^2(0)-e^{cos(0)}cos(0)

e^{c o s (0)} sin^{2} (0) - e^{c o s (0)} cos (0)

- e

Decimal Notation

- 2.71828 \dots

Solution steps

e^{c o s (0)} sin^{2} (0) - e^{c o s (0)} cos (0)

Use the following trivial identity:

cos (0) = 1

cos (0)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= e^{1} \cdot 0^{2} - e^{1} \cdot 1

Simplify

= - e

tan (- \frac{i}{3})

sin (tan (5 0^{\circ})) + sin (tan (31 0^{\circ}))

sec (6 4^{\circ})

cos (6) 2

cos (\frac{- 2}{2})

What is the value of e^{cos(0)}sin^2(0)-e^{cos(0)}cos(0) ?
The value of e^{cos(0)}sin^2(0)-e^{cos(0)}cos(0) is -e