What is the value of sin(-pi)+cos(-pi) ?

The value of sin(-pi)+cos(-pi) is -1

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sin(-pi)+cos(-pi)

sin (- π) + cos (- π)

- 1

Solution steps

sin (- π) + cos (- π)

Use the following property:

cos (- x) = cos (x)

cos (- π) = cos (π)

= sin (- π) + cos (π)

Use the following property:

sin (- x) = - sin (x)

sin (- π) = - sin (π)

= - sin (π) + cos (π)

Use the following trivial identity:

sin (π) = 0

Use the following trivial identity:

cos (π) = (- 1)

= - 0 - 1

Simplify

= - 1

12 sin (3 2^{\circ})

arcsin (\frac{- 1}{5})

sin (- \frac{2}{5})

0 sin (0) + cos (0)

2 (cos (\frac{7 π}{4}) + i sin (\frac{7 π}{4}))