What is the general solution for sin^2(x)-1=0 ?

The general solution for sin^2(x)-1=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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sin^2(x)-1=0

sin^{2} (x) - 1 = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (x) - 1 = 0

Solve by substitution

sin (x) = 1, sin (x) = - 1

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cot (6 0^{\circ})

sec^{2} (\frac{π}{2})

cos (3 θ) = - 1

sin (θ) + 1 = 0

sin (- \frac{π}{2})

What is the general solution for sin^2(x)-1=0 ?
The general solution for sin^2(x)-1=0 is x= pi/2+2pin,x=(3pi)/2+2pin