What is the value of (sin^2(pi)-4cos^2(pi))/pi ?

The value of (sin^2(pi)-4cos^2(pi))/pi is -4/pi

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(sin^2(pi)-4cos^2(pi))/pi

\frac{sin ^{2} ( π ) - 4 cos ^{2} ( π )}{π}

- \frac{4}{π}

Solution steps

\frac{sin ^{2} ( π ) - 4 cos ^{2} ( π )}{π}

Use the following trivial identity:

sin (π) = 0

Use the following trivial identity:

cos (π) = (- 1)

= \frac{0 ^{2} - 4 ( - 1 ) ^{2}}{π}

Simplify

\frac{0 ^{2} - 4 ( - 1 ) ^{2}}{π} : - \frac{4}{π}

= - \frac{4}{π}

\frac{4.8}{sin ( 5 4 ^{\circ} )}

500 \cdot sin (3 0^{\circ})

30 \cdot cos (3 7^{\circ})

5 tan^{2} (4 5^{\circ}) + 2 sec^{2} (4 5^{\circ})

4 - sin (3)

What is the value of (sin^2(pi)-4cos^2(pi))/pi ?
The value of (sin^2(pi)-4cos^2(pi))/pi is -4/pi