What is the value of sec^2(-24pi)*(-11)pi ?

The value of sec^2(-24pi)*(-11)pi is -11pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sec^2(-24pi)*(-11)pi

sec^{2} (- 24 π) \cdot (- 11) π

- 11 π

Decimal Notation

- 34.55751 \dots

Solution steps

sec^{2} (- 24 π) (- 11) π

Simplify

= - 11 π sec^{2} (- 24 π)

Use the following property:

sec (- x) = sec (x)

sec (- 24 π) = sec (24 π)

= - 11 π sec^{2} (24 π)

sec (24 π) = sec (0)

sec (24 π)

Rewrite

24 π

2 π \cdot 12 + 0

= sec (2 π 12 + 0)

Apply the periodicity of

sec

sec (x + 2 π \cdot k) = sec (x)

sec (2 π \cdot 12 + 0) = sec (0)

= sec (0)

= - 11 π sec^{2} (0)

Use the following trivial identity:

sec (0) = 1

sec (0)

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= 1

= - 11 π 1^{2}

Simplify

= - 11 π

tan (arccos (\frac{12}{13}))

\frac{1}{cos ( 6 0 ^{\circ} )}

cos (7 2^{\circ}) cos (13 0^{\circ}) + sin (7 2^{\circ}) sin (13 0^{\circ})

cos (7 0^{\circ}) \cdot cos (4 0^{\circ}) + sin (7 0^{\circ}) \cdot sin (4 0^{\circ})

arcsec (- 4)

What is the value of sec^2(-24pi)*(-11)pi ?
The value of sec^2(-24pi)*(-11)pi is -11pi