What is the value of cos((17pi)/6)*sec(-60)+cot(210) ?

The value of cos((17pi)/6)*sec(-60)+cot(210) is 0

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cos((17pi)/6)*sec(-60)+cot(210)

cos (\frac{17 π}{6}) \cdot sec (- 6 0^{\circ}) + cot (21 0^{\circ})

0

Solution steps

cos (51 0^{\circ}) sec (- 6 0^{\circ}) + cot (21 0^{\circ})

Use the following property:

sec (- x) = sec (x)

sec (- 6 0^{\circ}) = sec (6 0^{\circ})

= cos (51 0^{\circ}) sec (6 0^{\circ}) + cot (21 0^{\circ})

cos (51 0^{\circ}) = cos (15 0^{\circ})

= cos (15 0^{\circ}) sec (6 0^{\circ}) + cot (21 0^{\circ})

cot (21 0^{\circ}) = cot (3 0^{\circ})

= cos (15 0^{\circ}) sec (6 0^{\circ}) + cot (3 0^{\circ})

Use the following trivial identity:

cos (15 0^{\circ}) = - \frac{3}{2}

Use the following trivial identity:

sec (6 0^{\circ}) = 2

Use the following trivial identity:

cot (3 0^{\circ}) = 3

= (- \frac{3}{2}) \cdot 2 + 3

Simplify

(- \frac{3}{2}) \cdot 2 + 3 : 0

= 0

sec (\frac{19 π}{3})

- cos (\frac{π}{2} + \frac{π}{2})

sin (arccos (\frac{2}{9}))

\frac{3.7}{tan ( 4.6 )}

ln (2 + tan (\frac{π}{16}))

What is the value of cos((17pi)/6)*sec(-60)+cot(210) ?
The value of cos((17pi)/6)*sec(-60)+cot(210) is 0