What is the value of 14sin^2(2pi)+16cos^2(2pi) ?

The value of 14sin^2(2pi)+16cos^2(2pi) is 16

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14sin^2(2pi)+16cos^2(2pi)

14 sin^{2} (2 π) + 16 cos^{2} (2 π)

16

Solution steps

14 sin^{2} (2 π) + 16 cos^{2} (2 π)

sin (2 π) = sin (0)

= 14 sin^{2} (0) + 16 cos^{2} (2 π)

cos (2 π) = cos (0)

= 14 sin^{2} (0) + 16 cos^{2} (0)

Use the following trivial identity:

sin (0) = 0

Use the following trivial identity:

cos (0) = 1

= 14 \cdot 0^{2} + 16 \cdot 1^{2}

Simplify

= 16

3 cos (5 0^{\circ})

cos (3 \cdot \frac{π}{6})

cot (- \frac{21 π}{4})

tan (arccos (\frac{10}{26}))

cos (- 93 0^{\circ})

What is the value of 14sin^2(2pi)+16cos^2(2pi) ?
The value of 14sin^2(2pi)+16cos^2(2pi) is 16