What is the value of sin(120)-tan(120) ?

The value of sin(120)-tan(120) is (sqrt(3))/2+sqrt(3)

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sin(120)-tan(120)

sin (12 0^{\circ}) - tan (12 0^{\circ})

\frac{3}{2} + 3

Solution steps

sin (12 0^{\circ}) - tan (12 0^{\circ})

Use the following trivial identity:

sin (12 0^{\circ}) = \frac{3}{2}

Rewrite using trig identities:

tan (12 0^{\circ}) = - 3

= \frac{3}{2} - (- 3)

Simplify

= \frac{3}{2} + 3

sin (1 6^{\circ}) \cdot \frac{352}{sin ( 5 2 ^{\circ} )}

\frac{1 - cos ( 1 - 1 )}{( 1 - 1 ) sin ( 1 - 1 )}

- cos (2) (0)

1 - cos^{2} (2 4^{\circ}) - cos^{2} (6 6^{\circ})

tan (25.8 4^{\circ})

What is the value of sin(120)-tan(120) ?
The value of sin(120)-tan(120) is (sqrt(3))/2+sqrt(3)