en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tanh(5)

Solution

tanh (5)

Solution

\frac{e ^{10} - 1}{e ^{10} + 1}

+1

Solution steps

tanh (5)

Use the Hyperbolic identity:

tanh (x) = \frac{e ^{x} - e ^{- x}}{e ^{x} + e ^{- x}}

= \frac{e ^{5} - e ^{- 5}}{e ^{5} + e ^{- 5}}

\frac{e ^{5} - e ^{- 5}}{e ^{5} + e ^{- 5}} = \frac{e ^{10} - 1}{e ^{10} + 1}

= \frac{e ^{10} - 1}{e ^{10} + 1}

Popular Examples

7 cos (3.8 π)

sin (\frac{13}{12})

arcsin (0.857)

(sin(45))/(sin(56.31))

\frac{sin ( 4 5 ^{\circ} )}{sin ( 56.3 1 ^{\circ} )}

arctan (0.0875)

Frequently Asked Questions (FAQ)

What is the value of tanh(5) ?
The value of tanh(5) is (e^{10}-1)/(e^{10)+1}