What is the value of 9.8cos(75) ?

The value of 9.8cos(75) is (49(sqrt(6)-sqrt(2)))/(20)

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9.8cos(75)

9.8 cos (7 5^{\circ})

\frac{49 ( 6 - 2 )}{20}

Solution steps

9.8 cos (7 5^{\circ})

= \frac{49}{5} cos (7 5^{\circ})

Rewrite using trig identities:

cos (7 5^{\circ}) = \frac{6 - 2}{4}

= \frac{49}{5} \cdot \frac{6 - 2}{4}

Simplify

\frac{49}{5} \cdot \frac{6 - 2}{4} : \frac{49 ( 6 - 2 )}{20}

= \frac{49 ( 6 - 2 )}{20}

1 + cos (3 0^{\circ})

2 cos^{2} (\frac{3 π}{5}) - 1

\frac{4}{cos ( 5 5 ^{\circ} )}

- arctan (\frac{1 0 ^{- 1} \cdot 10}{- 1 0 ^{- 8} \cdot 1 0 ^{2} + 1})

[arcsec (\frac{5}{3}) + arcsin (\frac{5}{13})]

What is the value of 9.8cos(75) ?
The value of 9.8cos(75) is (49(sqrt(6)-sqrt(2)))/(20)