What is the value of (sin(60)+cos(60))^2 ?

The value of (sin(60)+cos(60))^2 is (2+sqrt(3))/2

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(sin(60)+cos(60))^2

(sin (6 0^{\circ}) + cos (6 0^{\circ}))^{2}

\frac{2 + 3}{2}

Solution steps

(sin (6 0^{\circ}) + cos (6 0^{\circ}))^{2}

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

= (\frac{3}{2} + \frac{1}{2})^{2}

Simplify

(\frac{3}{2} + \frac{1}{2})^{2} : \frac{2 + 3}{2}

= \frac{2 + 3}{2}

100 \cdot sin (1 5^{\circ})

1 + tan^{2} (\frac{π}{4})

arctan (\frac{2.5}{4})

tan (\frac{π}{3}) - tan (\frac{π}{6})

cos (\frac{2 π}{3}) - arctan (1)

What is the value of (sin(60)+cos(60))^2 ?
The value of (sin(60)+cos(60))^2 is (2+sqrt(3))/2